l Help 7b Homework #7 Begin Date: 3/27/2018 12:01:00 AM-Due Date: 4/2/2018 11.39
ID: 2034230 • Letter: L
Question
l Help 7b Homework #7 Begin Date: 3/27/2018 12:01:00 AM-Due Date: 4/2/2018 11.39:00 PM End Date: 4/7/2018 12:00:00 AM (17%) Problem 6: An electron moving at 3.5x 1° m s m a 1.5 T magnetic field experiences a magnetic force of 1.75 x 10 16 N what angle (in degrees, between o and 90") does the velocity of the electron make with the magnetic field? Grade Summary Pteetal 96% oasin acos atan) acotano Attempts remaiming (2% per attempt Degrees RadiansN Subt Tha electro bas a segatice chacge, bat we are lookoing for a poste ungle so you m d to take an sbeouze alue scmebre ???-?+ r Prtsc Backspace NumExplanation / Answer
Magnetic force is given by:
F = q*VxB
F = q*V*B*sin theta
sin theta = F/(q*V*B)
Using given values
sin theta = 1.75*10^-16/(1.6*10^-19*3.9*10^3*1.5)
sin theta = 0.18696
theta = arcsin (0.18696) = 10.77 deg
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