Rigid Objects in Equilibrium, Center of Gravity person is standing on a level fl

Question

Rigid Objects in Equilibrium, Center of Gravity person is standing on a level floor. His head, upper torso, Section 9.2 Section 9.3 1 arms, and hands together weigh 438 N and have a center ofc gravity that is 1.28 m above the floor. His upper legs weigh 144 N and have a center of gravity that is 0.760 m above the floor. Finally, his lower S legs and feet together weigh 87 N and have a center of gravity that is 0. center of gravity for his entire body 18 T tw 250 m above the floor. Relative to the floor, find the location of the 12The drawing shows a per- son (weight, W 584 N) tha wh the doing push-ups. Find the normal force exerted by the floor on each hand and each foot, assum- ing that the person holds this position. 13. ssm mmh A hiker, who weighs 985 N, is strolling through the woods and crosses a small horizontal bridge. The bridge is uniform, weighs 3610 N, and rests on two concrete supports, one at each end. He stops one-fifth of the way along the bridge. 0.840 m ,0.410 m

Explanation / Answer

There will be three force on the FBD

Fh and Ff working upward and "mg" downward.

Total Fy = 0

Fh + Ff - mg = 0

Fh + Ff = 584 N

total torque about center of body = 0

Fh*(0.410) - Ff*0.840 = 0

Ff = Fh*(0.41/0.84)

Ff = 0.488*Fh

Fh + Ff = 584 N

Fh + 0.488*Fh = 584 N

Fh*(1 + 0.488) = 584 N

Fh*1.488 = 584 N

Fh = 584/1.488

Fh = 392.47

Force on each hand = 392.47/2 = 196.23 N

Ff = 0.488*Fh = 0.488*392.47 = 191.52 N

Force on each foot = 191.52/2 = 95.76 N

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