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? O E ? Safari File Edit View History Bookmarks Window Help 42% [?, Wed 8:35 PM webassign.net CH 14 Physics question | Chegg.com My Noses O Auk Your Teacher 16. 2/10 points | Previous Answers SerPSET9 14.P.031.MI.SA. This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part. Tutorial Exercise A plastic sphere floats in water with 46.0% of its volume submerged. This same sphere floats in glycerin with 23.9% of its volume submerged. Determine the densities of the unknown fluid and the sphere (a) Determine the densities of the glycerin. (b) Determine the densities of the sphere. Part 1 of 4-Conceptualize The sphere has a density of about half that of water if 50% of its volume sinks, and a somewhat higher density if more than half sinks. The sphere floats higher in glycerin, so glycerin has a higher density than that of water Part 2 of 4-Categorize The sphere is a particle in equilibrium. The buoyant force supports the weight of the sphere Part 3 of 4-Analyze

Explanation / Answer

In water,

pplastic*Vball*g = 0.46*Vball*pwater*g

g and Vball will cancel on both sides,

pplastic = 0.46*pwater  ------> pplastic = 460 kg/m3

similarly, for glycerin

pplastic*Vball*g = 0.239*Vball*pglycerin*g

after cancelling like terms, we get

pplastic = 0.239*pglycerin ------- > pglycerin = 1924.68 kg/m3

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