The figure below is a cross-sectional view of a coaxial cable. The center conduc

Question

The figure below is a cross-sectional view of a coaxial cable. The center conductor is surrounded by a rubber layer, an outer conductor, and another rubber layer. In a particular application, the current in the inner conductor is I1 = 1.10 A out of the page and the current in the outer conductor is I2 = 3.14 A into the page. Assuming the distance d = 1.00 mm, answer the following.

(a) Determine the magnitude and direction of the magnetic field at point a.

(b) Determine the magnitude and direction of the magnetic field at point b.

Explanation / Answer

a) at point a,

B = mue*I1/(2*pi*d)

= 4*pi*10^-7*1.1/(2*pi*1*10^-3)

= 2.2*10^-4 T

= 220 micro T

direction : upward

b) at point b,

Bnet = B2 - B1

= mue*I2/(2*pi*3*d) - mue*I1/(2*pi*3*d)

= mue*(I2-I1)/(2*pi*3*d)

= 4*pi*10^-7*(3.14 - 1.1)/(2*pi*3*1*10^-3)

= 1.36*10^-4 T

= 136 micro T

direction : downward

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