perpendicular to the magnetic field. If the magnetic field points out of the pag
ID: 2032158 • Letter: P
Question
perpendicular to the magnetic field. If the magnetic field points out of the page and the charge moves to the West, then what is the direction of the resulting force? (In this problem we use the points of the compass for directions on the paper with North pointing to the top of the page, East pointing to the right, and 'into' and 'out of to indicate directions with respect to the page.) No South West Out of the page Into the page East ???? ??. Tries 1/2????? What is the magnitude of the force? in N) A: 1.26x10-11 B: 1.68x10-1 C: 2.23×10-1| D: 2.96x10-1 E: 3.94x10-11 F: 5.24x10-1| G: 6.97x10-1 H: 9.27×10-1 ???? Tries 0/2Explanation / Answer
Magnetic force is given by:
F = q*VxB
q = 1.31 uC = 1.31*10^-6 C
V = -5.90*10^5 i
B = 1.20 k
VxB = (-5.90*10^5 i)x(1.20 k)
VxB = -7.08*10^5*(ixk)
ixk = -j
VxB = 7.08*10^5 j
F = q*VxB
F = 1.31*10^-6*7.08*10^5 j
F = 9.27*10^-1 j N
Correct option is H
Direction will be towards North
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