(8c31p13) An oscillating LC circuit consisting of a 4.5 nF capacitor and a 3.2 m
ID: 2032116 • Letter: #
Question
(8c31p13) An oscillating LC circuit consisting of a 4.5 nF capacitor and a 3.2 mH coil has a maximum volatage of 4.0 V. What is the maximum charge on the capacitor? (in C) A: 1.35x10 8 B 1.80x108 C: 2.39108D: 3.18x 10-8E 4.23x 10-OF: 5.6310-8G: 7.49x 108H: 9.96x10 Submit Answer Tries 0/2 What is the maximum current through the circuit? (in A) A: 3.298 10.3?B: 3 71×10-??? 4.20× 10-3ED: 4.74× 10-3EE: 5.36 D: 4.74x10-31 -E: 5.36 x 10-31 10-3?F: 6.06 10-3 G: 6.84×10-31 Submit Answer Tries 0/2 What is the maximum energy stored in the magnetic field of the coil? in 3) A: 1.92x10 8 B: 2.25x10-8 Submit Answer Tries 0/2 C: 2.63 x 10 8?D: 3.08x10-8 E: 3.60x10-8 F: 4.21x108 OG: 4.93(10-8 8 H:577:10Explanation / Answer
Part a).
Maximum charge on capacitor Qmax = C* Vmax = 4.5* 10-9 * 4.0
Qmax = 1.8 *10-8 C
Option B is correct choice for Answer.
Part c).
Energy stored on capacitor U = (1/2)* C * V2 = 0.5 * 4.5 *10-9 *4.02 = 3.6 *10-8 J
Same energy is stored in coil when current is maximum in circuit, Umax = 3.6 *10-8 J
Option E is correct choice for Answer.
Part b)
U = (1/2)* L * I2
3.6 *10-8 = 0.5 * 3.2 *10-3 * I2
Maximum current in circuit I = ?(2.25* 10-5 )
Maximum current in circuit Imax = 4.74 *10-3 A
Option D is correct choice for Answer.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.