(8c22p25) In the figure (a), two curved plastic rods, one of charge +q = 1.8010-
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(8c22p25) In the figure (a), two curved plastic rods, one of charge +q = 1.8010-5 C and the other of charge -q, form a circle of radius R = 0.08 m in an xy plane. The x axis passes through their connecting points, and the charge is distributed uniformly on both rods. What are the magnitude and direction of the electric field E produced at P, the center of the circle? Ex?
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(8c22p25) In the figure (a), two curved plastic rods, one of charge +q = 1.800-5 C and the other of charge -q, form a circle of radius R = 0.08 m in an xy plane. The x axis passes through their connecting points, and the charge is distributed uniformly on both rods. What are the magnitude and direction of the electric field E produced at P, the center of the circle? Ex?Explanation / Answer
Assume rods are made of charge elements, consider an element of charge dq =(q/piR)dl Consider symmetrical pair of elements,sin components cancel, cos components add up contrbution of 1 element dE= [kdq/R^2]cosO dE =[kq/piR*R^2]dlcosO dE =[kq/piR*R^2]RcosOdO integrating,O changes from+90 to-90 E =[kq/piR*R^2]R(1+1) E = 2[kq/pi*R^2] The negative rod willcontribute equal amount in same direction Total E=4[kq/pi*R^2] E =4*9*10^9*11.3*10^-12/3.1416*0.042*0.042… N/C The magnitude of the electric field produced at P, the center of the circle is 73.4 N/C towards the mid point of negative rod
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