It IS NOT 5.40 * 10^8 Safari File Edit View History Bookmarks Window Help * 53%

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It IS NOT 5.40 * 10^8

Safari File Edit View History Bookmarks Window Help * 53% CO Mon 11:12 PM Q ? 0 session.masteringphysics.com Ch. 12 HW Problem 12.97 9 of 10 Part A A neutron star is the compact remnant of a very large star that has exploded. Suppose that right after one such explosion, when much of the star's inertia has been blasted away, the star's remaining core has an inertia of 4 x 103°kg, a radius of 13 x 108m, and completes one revolution every fve days. Assume negligible loss of inertia What is the new spin rate once the core gravitationally collapses into a neutron star of radius 25 km during the collapse Express your answer using two significant digits. times per second Submit Incorrect; Try Again; 5 attempts remaining Provide Feedback Next >

Explanation / Answer

angular momentum of system will be conserved,

Li = Lf

Ii wi = If wf

(0.4 M R^2 ) w0 = (0.4 M R'^2) w

(R/R')^2 w0 = w

w = (13 x 10^8 / 25 x 10^3)^2 (2pi / (5 x 24 x 3600s))

{ w = 2pi / T}

w = 39328 rad/s

f = w / 2pi = 6260 times per second.

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