nm Now we\'ll apply the thin-lens equation to the eye When light enters your eye
ID: 2031613 • Letter: N
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nm Now we'll apply the thin-lens equation to the eye When light enters your eye, most of the focusing happens at the interface between the air and the cornea (the outermost element of the eye). The eye also has a double-convex lens, lying behind the cornea, that completes the job of forming an image on the retina. (The lens also enables us to shift our distance of focus; it gets rounder for near vision and flatter for far vision.) The crystalline lens has an index of refraction of about 1.40. (a) For the lens shown (Figure 1), find the focal length. (b) If you could consider this lens in isolation from the rest of the eye, what would the image distance be for an object 0.20 m in front of this lens? Part (b): The object distance is do0.20 m- 200 mm. Using the thin-lens equation, 1/f-1/do + 1/di,We obtain 200 mIn ITIII di7.5 mm REFLECT The image is slightly farther from the lens than it would be for an infinitely distant object. As expected for a converging lens, the focal length is positive Part A Practice Problem: Suppose that to observe an object that is 4.70 m away, the lens in your eye flattens out so that it acts like the crystalline lens in the example, except with radii of curvature of C1 10.6 mm and C2 9.65 mm. How far behind the lens would the image form in this case? gure 1 of 1 Express your answer to three significant figures and pay attention to units 5.5 mm 6.0 mm C2 n1.40 Submit Request AnswerExplanation / Answer
From thin lens equation
1/f = (n-1)*(1/C1 - 1/C2)
C1 = 10.6 mm
C2 = -9.65 mm
1/f = (1.4 - 1)*(1/10.6 + 1/9.65)
focal length of eye lens f = 12.6 mm
object distane d0 = 4.7 m = 4.7*10^3 m = 470 mm
image distance di = ?
focal length f = 12.6 mm =
1/do + 1/di = 1/f
1/470 + 1/di = 1/12.6
image distance di = 13 mm <<<---------ANSWER
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