Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

nissions Used (a) A piston at 5.3 atm contains a gas that occupies a volume of 3

ID: 560516 • Letter: N

Question

nissions Used (a) A piston at 5.3 atm contains a gas that occupies a volume of 3.5 L. What pressure would have to be placed on the piston to force the volume to adjust to 1.29 L? atm (b) A piston at -65.0°C contains a gas that occupies a volume of 2.5 L. To what temperature would the gas have to be heated to increase the volume to 4.9 L at constant pressure? eC (c) A piston at 195 torr contains a gas that occupies a volume of 4.7 L. What pressure would have to be placed on the piston to force the volume to adjust to 0.71 L? atm

Explanation / Answer

a)

we have:

P1 = 5.3 atm

V1 = 3.5 L

V2 = 1.29 L

we have below equation to be used:

P1*V1 = P2*V2

5.3 atm * 3.5 L = P2 * 1.29 L

P2 = 14.4 atm

Answer: 14.4 atm

b)

we have:

T1 = -65.0 oC

= (-65.0+273) K

= 208 K

V1 = 2.5 L

V2 = 4.9 L

we have below equation to be used:

V1/T1 = V2/T2

2.5 L / 208.0 K = 4.9 L / T2

T2 = 407.68 K

T2 = 134.68 oC

Answer: 135 oC

c)

we have:

P1 = 195 torr

V1 = 4.7 L

V2 = 0.71 L

we have below equation to be used:

P1*V1 = P2*V2

195 torr * 4.7 L = P2 * 0.71 L

P2 = 1291 torr

P2 = 1291/760 atm

P2 = 1.70 atm

Answer: 1.70 atm