Unpolarized light that has an intensity of lo 850 W/m2 is incident on a series o

Question

Unpolarized light that has an intensity of lo 850 W/m2 is incident on a series of polarizing filters as shown in Figure. 0° a? 90° 1) If the itensity of the light after the final fiter is 13-66 w/m2, what is the orientation of the second polarizer reative to the x axis (denoted q in the figure)? Enter the smaler possible angle between 0 and 90 Hint: cos(90 )in and 2 sin cos -: sin 20. (Express your answer to two significant figures.) You currently have O submissions for this question. Only 10 submission are alowed You can make TO more submissions for this question.

Explanation / Answer

Intensity of light coming from first polarizer I1 = Io/2

theta is the angle made by second polariaer with the vertical

Intensity of light coming from second polarizer I2 = I1*(costheta)^2 = (Io/2)*(costheta)^2

Intensity of light coming from third polarizer I3 = I2*(cos(90-theta))^2 = I2*(sintheta)^2 = (Io/2)*(costheta)^2*(sintheta)^2

given I3 = 66 W/m^2

(Io/2)*(costheta)^2*(sintheta)^2 = 66

(I0/2)*(sintheta*costheta)^2 = 66

(I0/8)*(2*sintheta*costheta)^2 = 66

I0/8 *(sin(2theta))^2 = 66

(850/8)*(sin(2theta))^2 = 66

(sin(2theta))^2 = 66*8/850

sin(2theta) = 0.788

theta = 26 degrees

angel made with x axis q = 90 - theta = 64

Related Questions

Navigate

• Browse (All)
• Browse U
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.