Figure 1 Kirchhoff\'s Rules: rcuit shown in figure 2 (resistors in series). Sugg

Question

Figure 1 Kirchhoff's Rules: rcuit shown in figure 2 (resistors in series). Suggested voltage from power supply is 3 (V) throughout the experiment, Note: make sure that "+"terminal of ammeter is connected to""terminal of the power supply. Write down the ammeter reading in table 2. A) 12 R2 R3 Figure 2 Figure 3 Using digital multimeter, measure the voltage across R2 and R3, write down this data in table 3. Perform the calculations in table 3 and compare the sum of voltages across R2 and R3 with the voltage from the power supply. CAUTION: Ammeter will blow up if connected directly across the power source Ruining an ammeter is EXPENSIVE!!

Explanation / Answer

part 1)

from table 2

I1(A) = I2(A) = 0.16 A

from table 3

V2 = Voltage across resistor R2 = 0.68 V

V3 = Voltage across resistor R3 = 2.26 V

Now we know R = V/I

R2 = V2/I = 0.68/0.16 = 4.25 ohms

R3 = V3/I = 2.26/0.16 = 14.125 ohms

Part 2)

Combined Resistance in series = R2 + R3 = 5 + 15.7 = 20.7 ohms

Combined resistance in parallel = R2*R3/(R2+R3) = 5*15.7/(5+15.7) = 3.79 ohms

part 3)

table 2

Percentage diffference = ((I1(A) - Ioriginal)/(Ioriginal))*100

Ioriginal = V/(R2 + R3) = 3/(5+15.7) = 0.14 A

I1(A) = 0.16 A
% difference = (0.16-0.14)/0.14 * 100 = 14.285 %

Table 3:

VR2 + VR3 = 0.68+2.26 = 2.94 V

% difference = (3-2.94)/(3) * 100 = 2%

Table 4:

I1 + I2 = 0.8

Ioriginal = V/R

R = R2*R3/(R2+R3) = 5*15.7/(5+15.7) = 3.79 ohms

Ioriginal = 3/3.79 = 0.79 A

% difference = ((0.8-0.79)/0.79)*100 = 1.265 %

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