(896) Problem 7: A baseball of mass m,-0.39 kg is thrown at another ball hanging
ID: 2030522 • Letter: #
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(896) Problem 7: A baseball of mass m,-0.39 kg is thrown at another ball hanging from the ceiling by a length of string I 1.95 m. The second ball m 0.85 kg is initially at rest while the baseball has an initial horizontal velocity of V 3.5 m/s. After the collision the first baseball falls straight down (no horizontal velocity.) Randomized Variables 0.39 kg m 0.85 kg L 1.95 m n-3.5 mis m, 2Otheexpertta.com 50% Part (a) Select an expression for the magnitude of the closest distance from the ceiling the second ball will reach d 50% Part (b) what is the angle that the string makes with the vertical at the highest point of travel in degrees? Grade Summary Deductions 30% Potential 70% 0-40.46 sino 7 89 HOME coso cotan asin acos0 atan acotan inh0 Submissiens Attempts remaining:2 (30% per attempt) detailed view cosh) tanhcotanh0 END 30% Degrees O Radians BACKSPACE DEL CLEAR Submit Hint I give up I lints: 30% deduction per hint. Hints remaining: 2 FeedbackExplanation / Answer
h = L – L * cos
h = 1.5 – 1.95 * cos
1.95 * cos = 1.95 – h
cos = 1 – h/1.95
PE = m * g * h, KE = 1/2 * m * v^2
m * g * h = 1/2 * m * v^2
h = 1/2* v^2/9.8 = v^2/19.6
Initial momentum of 1st ball = 0.39 * 3.5 = 1.365
nitial velocity of the 2nd ball.
0.85 * v = 1.365,
v = 1.365 ÷ 0.85 = 1.60 m/s(approxi)
h = (1.365 ÷ 0.85)^2/19.6
h = 0.1315 m
cos = 1 – 0.1315/1.95
cos = 0.9325
= 20o
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