(8%) Problem 9: A ball is thrown upward from die ground with inital velocity v 1

Question

(8%) Problem 9: A ball is thrown upward from die ground with inital velocity v 16 m's and reaches height of h above the ground before falling back down Take the upward direction to be positive. Refer to the figure. Neglect air resistance Assignment Status Click here for detailed view Problem Status 1 Completed 3%Part (a) what is the acceleration, in meters per second squared, to the ball when tain de an 2 Partial ptul , 9.81 6 Partial 7 Completed S Completed 9 Partia 10 sinO cotan sn acos) atan acotan sino cosh tn cotanh .Degrees ORadians Hie Feedbackdedation per feedback 12 13 - S% Part (b) what is dir velocity ofthe balLa mem per second, when 'treaches the top ofits tajectory? .. s". Pan (c) Ester an expression for the maxinum hright, A, the ball,eache, intern. ofs,and a u .. s% Pami d) Calculate the value of h, in meters da & s Part ()Eeran espression for the time it takes for the ball to travel from the ground to the top. At. in tems of 5% Part (f) Calculate the value of in seconds - s % Paz, (s) %hat is the soal daaplacement. in meters, ofthe ball gong drough its fiture motion traveling foa de pound nee bop and then falling back to the ground gong theough its estire otion raveling from the ground to dhe sop and Enter an expression for the total tise of flight of the ball the tume froes when d is lainched to mhen at lands back en the an S. Part (h) pe here to search

Explanation / Answer

A)

acceleration = -9.8 m/s2 <---- negative sign for downwards direction

b)

velocity of ball at the top = 0 m/s

c)

using equation of motion :

v^2 = u^2 + 2as

So, 0^2 = vi^2 - 2*a*h

So, h = vi^2/2a <------ answer

d)

h = 16^2/(2*9.81) = 13.05 m

e)

v = u + at

So, 0 = vi - a*t

So, t = vi/a <------- answer

Related Questions

Navigate

• Browse (All)
• Browse #
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.