A large capacitance of 1.80 mF is needed for a certain application. (e) Calculat

Question

A large capacitance of 1.80 mF is needed for a certain application. (e) Calculate the area (in m2) the parallel plates of such a capacitor must have if they are separated by 4.00 um of Teflon. m2 (b) What is the maximum voltage (in V) that can be applied? (c) Find the maximum charge (in C) that can be stored. (d) Calculate the volume (in m3) of Teflon alone in the capacitor. Additional Materials Reading 4. -1 points 16 19.6.PO57 My Notes Ask Your Find the total capacitance in micro farads of the combination of capacitors shown in the figure below. 2.5 uF 0.30 F

Explanation / Answer

here,

capacitance , C = 1.8 mF = 0.0018 F

a)

sepration between the plates , d = 4 * 10^-6 m

dielectric constant of Teflon , K = 2.1

let the area of each plate be A

C = K * area * e0 /d

0.0018 = 2.1 * area * 8.85 * 10^-12 /(4 * 10^-6)

area = 387 m^2

b)

dielectric strngth of Teflon , E = 7 * 10^7 V/m

the maximum voltage , Vm = E * d

Vm = 280 V

c)

the maximum charge , Q = C * V = 0.5 C

d)

the volume of teflon filled , V = area * d

V = 1.6 * 10^-3 m^3

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