1) Two isotopes of carbon, carbon-12 and carbon-13, have masses of 1.993x10^-26
ID: 2027963 • Letter: 1
Question
1)Two isotopes of carbon, carbon-12 and carbon-13, have masses of 1.993x10^-26 kg and 2.159 x 10^-26 kg, respectively. These two isotopes are singly ionized (+e) and each is given a speed of 6.88 x10^5 m/s. The ions then enter the bending region of a mass spectrometer where the magnetic field is 0.8700 T. Determine the spatial separation between the two isotopes after they have traveled through a half-circle.
2)
A copper rod of length 0.91 m is lying on a frictionless table (see the drawing). Each end of the rod is attached to a fixed wire by an unstretched spring that has a spring constant of k = 76 N/m. A magnetic field with a strength of 0.17 T is oriented perpendicular to the surface of the table.
If the current is 13 A, by how much does each spring stretch?
Explanation / Answer
The spatial difference between two isotopes after they have travelled through a half circle is d = 2( r_2 - r_1 ) = 2 ( m_2 v / eB )( - 2 ( m_1 v / e B ) = (2 v / e B ) ( m_2 - m_1 ) masses of two isotopes are m_2 = 2.159*10^-26 kg , m_1 = 1.993*10^-26 kg speed of the isotopes is v = 6.88*10^5 m/s magnetic field is B = 0.8700 T d = 2 * 6.88*10^5 m/s / 1.6*10^-19 C * 0.8700T ( 2.159*10^-26 kg - 1.993*10^-26 kg ) = 0.0164m = 1.64 cm according to cramster rule only one question to be answerd please post second question another post i will answer you thank u ( please give figure )Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.