problem set 2-Problem set 2.pdf Chegg Study Guided Solution × + × 4of 8 f Facebo
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problem set 2-Problem set 2.pdf Chegg Study Guided Solution × + × 4of 8 f Facebook https://uoit bbcswebdav/pid-1047741-dt-content-rid-6334328_1/courses/20180 a Search - + Automatic Zoom 5. (5) You are working with a farmer who has two varieties of true-breeding corn plants The Durham variety has dominant alleles for short stature (S), yellow leaf colour (Y) and crinkled leaves (C). The UOIT variety has the recessive alleles for all three genes; tall stature (s), green leaf colour (y), and smooth leaves (c). The farmer has mapped the genes and tells you that they are linked as shown below: 7 m.u 18 m.u The farmer has produced an F1 hybrid between the two varieties and has backcrossed this to the UOIT variety. Assuming that there is no interference, he wants you to tell him: a. The proportion of the backcrossed progeny that will be phenotypically identical to the b. The proportion of the backcrossed progeny that will be phenotypically identical to the C. The proportion of the backcrossed progeny that will have the stature and leaf texture of d. The proportion of the backcrossed offspring that will have the stature and leaf colour of Durham variety for all three traits UOIT variety for all three traits Durham variety but the leaf colour of the UOIT variety Durham variety but the leaf texture of the UOIT variety 12:34 AM O Type here to search f ^4x ENG 2018-02-28Explanation / Answer
The steps involved in this problem:
1. Calculation of DCO from COC
2. Calculation of SCO and
3. Calculation of PCO.
1. Calculation of DCO freequency : (E2)
As the interference or COC is not mentioned here, condiering that the interference is 0,
hence the
COC = 1.
COC = Prop of ODCO/ Prop of EDCO.
=> 1 = Prof of ODCO/ (7/100 X 18/100) => DCO = 1 X 0.07 X 0.18 = 0.0126
The Freequency of DCO = 0.0126
the freequency of individual category = 0.0126 / 2 = 0.0063
2. Calculation of SCO:. (E1)
The Distiance between two genes= Prop of SCO+ Prop of DCO.
So, Prop of SCO = Distiance between two genes - Prop of DCO.
The freequency = Prop of SCO * Total no of progeny
As each category consists two catergories, the freequency of individual category = Total
freequency / 2.
Between first pair of genes =
The Distance = 7, The proportion = 7/100 = 0.07
Prop of SCO = 0.07- 0.0126 = 0.0574
the freequency of individual category = 0.0574 / 2 = 0.0287
Between second pair of genes =
The Distance = 18, The proportion = 18/100 = 0.18
Prop of SCO = 0.18- 0.0126 = 0.1674
the freequency of individual category = 0.1674/2 = 0.0837
3. Calculation of PCO: (E0):
Parental combinations = Total freequency - SCO - DCO
=> 1-0.0126-0.0574-0.1674 = 0.7626
the freequency of individual category = 0.7626/2 = 0.3813
The answers are
a. 0.3813 (Because that phenotype belongs to parental category)
b. 0.3813 (Because that phenotype belongs to parental category)
c. 0.0063 (Because that phenotype belongs to DCO category)
d. 0.0837 (Because that phenotype belongs to sco between second pair of genes category)
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