problem 22We have the following integral:TP (1+x)so23 =I Normally, the error bet

Question

problem 22We have the following integral:TP (1+x)so23 =I Normally, the error between the actual value of an integral and the result given by composite trapezoidal rule decreases by O(h^2) and the error given by the corrected trapezoidal rule decreases by O(h^4). However, for the above integral, the errors for both the composite AND corrected trapezoidal decrease at the same rate. QUESTION: Please explain why! Do not work out each rule and then show they are the same. I have asked this question twice before and have received an inappropriate answer. Thank you!

Explanation / Answer

Dear Student,

We are using the same equation for finding the error with the help of two methods. Obviously the two methods would give us two different errors. But since we are using single equation for both the error decrement is at the same rate for both the methods. Just like y=mx+c gives you one single slope i,e same rate of decrement or increment of y .

Thank You. Have a Nice Day.

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