<p>A pair of charged conducting plates produces a uniform field of 12,000N/C, di

Question

<p>A pair of charged conducting plates produces a uniform field of 12,000N/C, directed to the right, between the plates. The seperation of the plates is 40mm. In the figure, an electron is projected, directly toward plate B, with an initial velocity v_o=2.0x10⁷ m/s. the velocity of the electron as it strikes plate B is closest to:</p>
<p>-------------</p>
<p>three charges of magnitude 3.0x10^-4 C each located at x=1.0m, y=0.0m, at x=0.0m, y=0.0m, and at x=-1.0m, y=0.0m. the one in the middle is negative, while the other two are positive. what is the net coulombic force exerted by them on a negative 3.0x10^-5 C charge located at x=0.0m, y=2.0m? (the value of k is 9.0x10⁹ N.m²/C²)</p>

Explanation / Answer

The force due to an electric field is given by: F = qE, however for an electron F = qE (in the opposite direction-- the electron will slow down).

F = ma

-qE = ma

==> a = -qE / m = (1.602 x 10-19 C)(12000 N/C) / (9.109 x 10-31 kg) = -2.11 x 1015 m/s2

vf = (v02 + 2ad) = ((2.0 x 107 m/s)2 + 2(-2.11 x 1015 m/s2)(40 mm)) = 1.52 x 107 m/s

If you repost the second question separately, I will answer it.

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