<p>A 21.0-kg block oscillates back and forth along a straight line on a friction

Question

<p>A 21.0-kg block oscillates back and forth along a straight line on a frictionless horizontal surface. Its displacement from the origin is given by</p>
<p><img src="https://s3.amazonaws.com/answer-board-image/cramster-equation-20111130848146345823969406130726014.gif" alt="" align="absmiddle" /></p>
<p>What is the oscillation frequency, what is the maximum speed acquired by the block, what is the maximum acceleration of the block, and what is the magnitude of x(t) when the block experiences its maximum acceleration?</p>

Explanation / Answer

m = 21 kg

= 16 rad/s

f = 16/2 = 2.547 sec-1

maximum speed = Amplitude* = 0.18*16 = 2.88 m/s

maximum acceleration = Amplitude*2 = 0.18*16*16 = 46.08 m/s2

magnitude of x(t) will be 18 cm because the cos term will be -1 in that case coz it is a case of maximum acceleration and hence, at that time itself, we would be having maximum acceleration

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