A 4.0 kg object is moving at 5.0m/s NORTH. It strikes a 6.0 kg object moving WES

Question

A 4.0 kg object is moving at 5.0m/s NORTH. It strikes a 6.0 kg object moving WEST at 2.0 m/s. The objects have completely stuck together. What is the velocity of the 4.0 kg object and at what angle is it moving?

m1= 4.0 kg v1= 5.0 m/s
m2= 6.0 kg v2= 2.0 m/s

I found the V after collision= 2.33 m/s

I'm having trouble finding the angle the object os moving north of west.

I thought to use tan^-1 [(m1v1sin(theta) + m2v2)/ m1v1sin(theta)] =58 degrees.
... Is this anything close to doing it right??

Thanks!!

Explanation / Answer

I get 59 degrees north of west.

But I'm not sure I understnad your technique...what theta are you taking the sine of?

The momentum components stay the same; 20 kg-m/s north and 12 kg-m/s west; all applied to one 10 kg object, so your velocity is right, and the direction is just arctangent (20/12), directed to the northwest.

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