***Two parter because I\'ve already figured out the first parts of both question
ID: 2022322 • Letter: #
Question
***Two parter because I've already figured out the first parts of both questions***
1) A "swing" ride at a carnival consists of chairs that are swung in a circle by 12.0 m cables attached to a vertical rotating pole, as the drawing shows. ( = 55.5°) Suppose the total mass of a chair and its occupant is 200 kg.
(a) Determine the tension in the cable attached to the chair.
N
(b) Find the speed of the chair.
m/s
2) One 2.7 kg paint bucket is hanging by a massless cord from another 2.7 kg paint bucket, also hanging by a massless cord, as shown in Fig. 4-44.
(lower cord) N (upper cord) NExplanation / Answer
1 b )Horizontal component of T provides the centripetal force Fc = mv²/R • sin55.5 = Fc/T .... Fc = T sin55.5 = 4975*0.8668 .... Fc = 4312.33 N • R = 12 cos(90-55.5) = 11.98m Fc = mv²/R .... v = v(Fc*R/m) = v(4312.33*11.98/200) ..... ?v = 16.07m/s 2 b) b) lower - F=ma Because you are pulling up, the acceleration gets added to 9.81 F=(2.7)(11.61) upper - F=ma Once again add the two masses. F=(7.29)(11.61)
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