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While a person is walking, his arms (with typical lengths 70 cm measured from th

ID: 2022287 • Letter: W

Question

While a person is walking, his arms (with typical lengths 70 cm measured from the shoulder joint) swing through approximately a 45 degree angle in 0.5 s. As a reasonable approximation, we can assume that the arm moves with constant speed during each swing.
Find the magnitude of the force that the blood vessel must exert on the drop of blood.

(I've already calculated the acceleration of 1.1 g drop of blood to be 1.7m/s^2.)

I've tried using n-w = m(v^2/r). Its not going so well. Is this the correct equation? Can you get me started? Thank you.

Explanation / Answer

I don't see where 1.1 g came from, that's not in the problem statement.

But based on what you've said, radius of 0.7 m, moving /4 radians in 0.5 s means angular velocity, , is about 1.57 rad/s

So I agree with your acceleration, 2r = 1.73 m/s2

What force do you mean? If you mean centripetal, then it's just m times that acceleration. Something that has a mass of 1.1 g = 0.0011 kg has a force of ma = 0.0019 N.