Use the values from PRACTICE IT to help you work this exercise. Find the horizon

Question

Use the values from PRACTICE IT to help you work this exercise. Find the horizontal distance the skier travels before coming to rest if the incline also has a coefficient of kinetic friction equal to 0.191. (The incline makes an angle = 20.0° with the horizontal.

Values from Practice it: Use the worked example above to help you solve this problem. A skier starts from rest at the top of a frictionless incline of height 20.0 m, as shown in the figure. As the bottom of the incline, the skier encounters a horizontal surface where the coefficient of kinetic friction between skis and snow is 0.191. (DONT NEEED TO BE ANSWERED, THIS IS GIVEN TO HELP SOLVE THE PROBLEM ABOVE)

Explanation / Answer

the coefficient of kinetic friction between skis and snow k = 0.191 speed v = {2gL(sin - k cos)}   ................ (1) from figure , sin = h/L length of the incline L = h/sin                                  = (20 m) /sin20                                  = 58.476 m so , speed v = {(2)(9.8 m/s2)(58.476 m)(sin20 - (0.191) cos20)}                = 13.64 m/s then the distance travelled on the horizontal rough surface is                  d = v2/2g                     = (13.64 m/s) / (2)(0.191)(9.8 m/s2)                     = 49.76 m then the distance travelled on the horizontal rough surface is                  d = v2/2g                     = (13.64 m/s) / (2)(0.191)(9.8 m/s2)                     = 49.76 m then the distance travelled on the horizontal rough surface is                  d = v2/2g                     = (13.64 m/s) / (2)(0.191)(9.8 m/s2)                     = 49.76 m

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