5-) Now consider the Atwood machine shown at the right. It is an example of pure

Question

5-) Now consider the Atwood machine shown at the right. It is an example of pure rotational motion; that is, the center of gravity of the pulley does not translate up/down or to the left/right. The pulley can be considered as a solid cylindrical disk. The hanging mass m= 5kg and M is 10kg. System goes through a purely rotational motion. The radius of the pulley is r=.5m and mass of the pulley is Mp =2kg
a-) Find the torque
b-) Tension T1 and T2
c-) Acceleration a

(m1 T1 go toward ceiling and m2 T2 go toward the ground)

Explanation / Answer

T_Net = summation F x R by definition of torque 2. F_Net = ma Newton's law but in this scenario, if you draw a force diagram for the block you have force of tension going up and mg going down. So F_Net = T -Mg Substituting for F_Net we get ma = T-mg or T = m(g+a) For 3 F_Net = ma But this time the forces are just the different parts of the atwood machine. 1 is going down, and one is going up so you subtract PLEASE RATE.

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