Magnitude of the resultant vector _________ What direction is the resultant vect
ID: 2017744 • Letter: M
Question
Magnitude of the resultant vector
_________
What direction is the resultant vector pointing in?
It has no magnitude so the direction is irrelevant.
Due east (along the positive x-axis)
Due north (along the positive y-axis)
Due west (along the negative x-axis)
Due south (along the negative y-axis)
A northeasterly direction (first quadrant)
A northwesterly direction (second quadrant)
A southwesterly direction (third quadrant)
A southeasterly direction (fourth quadrant)
.
What is the angle between the resultant vector and the horizontal? If the magnitude of the resultant is zero, then enter 'none'.
_________°
Explanation / Answer
magnitude of vector A = 41 angle A = 61 degreesvector A = 41 sin 61 i + 41 cos 61 j = 35.85 i + 19.87 j where i , j are the unit vectors along east and north directions respectively magnitude of vector B = 27 angle B= 72 degrees vector B = 27 cos 72 *(-i) + 27 sin 72 *(-j) = -27 cos 71 i -27 sin 72 j = - 8.79 i -25.67 j resultant vector A+B = 35.85 i + 19.87 j - 8.79 i -25.67 j = 27.06 i -5.8 j resulatant vector is in 4 th quadrant i.e., southeasterly direction (fourth quadrant)
magnitude of A+B is = [27.06^2 +(-5.8)^ 2] = 27.67 units let the resulatnt makes an angle with east along south direction then tan = 5.8 / 27.06 = 0.2143 = 12.09 degrees
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