In Figure P20.63, the rolling axle, 1.51 m long, is pushed along horizontal rail
ID: 2016813 • Letter: I
Question
In Figure P20.63, the rolling axle, 1.51 m long, is pushed along horizontal rails at aconstant speed v = 1.00 m/s.A resistor R = 0.401 isconnected to the rails at points a and b,directly opposite each other. (The wheels make good electricalcontact with the rails, so the axle, rails, and R form aclosed-loop circuit. The only significant resistance in the circuitis R.) A uniform magnetic field B = 0.0900 T is directed vertically downwards.Figure P20.63
(a) Find the induced current I in theresistor.
A
(b) What horizontal force is required to keepthe axle rolling at constant speed?
N
(c)Which end of the resistor, a or b, is at thehigher electric potential?
a
b
(d)After the axle rolls past the resistor, does the current inR reverse direction?
yes
no
Explanation / Answer
GIven lengthof axel L = 1.51 m speed of axel v = 1. 00 m/s magnitude of magnetic field B = 0.09 T emf induced in the axel = B L v = ( 0.09 T ) ( 1.51 m ) ( 1.00 m/s ) = 0.1359 V a) induced current in the resistor I = R = 0.1359 * 0.401 = 0.0544 A = 5.44*10^ -2 A b) horizontal force is required to keepthe axle rolling at constant speed F = I B L = 0.0544 * 0.09 * 1.51 = 7.39*10^ -3 N c) Here b is at a higher potential than a and the current goesfrom b to a through the resistor d) No, the velocity v of the rolling axle and the magnetic fieldB are unchanged .Thus the polarity is also unchanged.So, the current is directed to b to a in the resistor R. c) Here b is at a higher potential than a and the current goesfrom b to a through the resistor d) No, the velocity v of the rolling axle and the magnetic fieldB are unchanged .Thus the polarity is also unchanged.So, the current is directed to b to a in the resistor R.Related Questions
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