In Figure 17.40(b), q = 1.00 µC, b = 3.00 and c = 4.00. Enter \'infinity\' for t

Question

In Figure 17.40(b), q = 1.00 µC, b = 3.00 and c = 4.00.

Enter 'infinity' for the following answers where appropriate.

(a) Find the total electric field at x = 5.00 cm.
N/C

(b) Find the total electric field at x = 11.0 cm.
N/C

(c) If the charges are allowed to move and eventually be brought to rest by friction, what will the final charge configuration be? (That is, will there be a single charge, double charge, etc., and what will its value(s) be? List the charges from left to right if there are more than one, using the format '+3q,+q'. Include the sign for each charge.)

Explanation / Answer

(a)Electric Field is the field produced by any electric charge around it whose influence is observed when another charge is brought in that area where the field exists.The force F experienced by electric charge q is gives the Electric field linesThe electric field formula is given by,

E=F/q

If q and Q are two charges in space separated by the distance r. The Electric force is given by

F=kQq/r2

Substituting the electric force formula in the above electric field formula we getElectric Field Formula as

E=kQ/r2

Electric field is measured in N/C. Electric Field formula is used to find Electric field of any number of point charges given in space.

E=9* 109 *(10)-6 / (4/100)2

= 9*107/16

=0.5625 * 107N/C

(B) E= kQ/r2

= 9*109 * 4*10-6 /(3/100)2

= 4* 107N/C

(c)total charge=-bq+q+cq-q

=10-6(-3+1+4-1)

=10-6c

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