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1) A horseshoe magnet, in the plane of the paper, is shown below. If the positiv

ID: 2016075 • Letter: 1

Question

1) A horseshoe magnet, in the plane of the paper, is shown below. If the positive ion travels into the paper, between the magnetic field lines, the ion is deflected:

a. toward the N pole

b. toward the S pole

c. downward

d. upward

e. but really moves in a straight line

2) The long straight wire of an NMR machine below carries a 5.0 A current. At one instant, a hydrogen ion in the body (proton), 4.0 x 10 -3 m from the wire, travels at a speed of 1.5 x 10 5 m/s parallel to and in the same direction as the current. Solve for the magnitude and direction of the magnetic force that acts on the ion due to the wire's magnetic field. HINT: First, find the magnetic field from the wire that acts on the hydrogen ion.

Explanation / Answer

As all we know , when the mangetic is placed ,it ca create anmaount of mangetic field in the vicinityof the manget . This field can be assume by the magnetic lines of forces formed by around the magnet . Usually ,these lines of forces starting from North pole and end at South pole . so, when the positive ion (+ ion ) placed between the magnetic lines of forces , it (ion) can be deflected towards the south pole as the amgnetic field acting to-wards the south pole Ans : (b) (b) The long straight wire of an NMR machine below carries I = 5.0 A current. at a distance proton is located = d =  4.0 x 10 -3 m from the wire thus, Mgnetic field due to this currrent at this distance is ;           B = o I / 2 d              = 4 x10-7 (5 ) / 2 (4 x10-3)               = 2.5 x 10-4 T    Proton travels with speed :          V = 1.5 x105 m/s charge onthe proton : Q = + 1.6 x10-19 C Hence , Mangetic force acting on the proton is :     F = Q V B         = (1.6 x10-19)(1.5 x105)(2.5x10-4)         = 6 x 10-18 N