A generator at one end of a very long string creates a wave given by y=(5.0 cm)c

Question

A generator at one end of a very long string creates a wave given by

y=(5.0 cm)cos((p/2.)*(3.0 m-1x +5.0 s-1 * t)),

and at the other end creates the wave

y=(5.0 cm)cos((p/2.)*(3.0 m-1x -5.0 s-1 * t)).

frequency=1.25Hz

Wavelenth=1.33m

Speed=1.67 m/s

Define the origin to be at one end. How far from the end is the first node? (m)

Define the origin to be at one end. How far from the end is the second node? (m)

Define the origin to be at one end. How far from the end is the first antinode? (m)

Define the origin to be at one end. How far from the end is the second antinode? (m)

Explanation / Answer

The distance between one end to first node is d = /4 = (1.33 m)/4 =0.3325 m
The distance between one end to secondt node is d = /4 =3 (1.33 m)/4 =0.9975m
The distance between one end to first antinode is d = 0 The distance between one end to secondt antinode is d = /2 = (1.33 m)/2 =0.665 m

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