<p>Animal aggression. During mating season, bull elk engage in fierce fights by

Question

<p>Animal aggression. During mating season, bull elk engage in fierce fights by running head to head. Suppose a 500 { m kg} elk running northward at 45 { m km/h} crashes into a 580 { m kg} elk charging directly toward him at the same speed. The impact lasts 0.50 { m s}, and the animals lock horns.<br /><br />Find the magnitude of the velocity of the elk just after they lock horns.Find the magnitude of the velocity of the elk just after they lock horns.What average force does each elk exert on the other during this collision?</p>

Explanation / Answer

Despite your utter disrespect of units and spelling, the problem is easier to handle than it looks. What you want to do first is to get the facts: mass of bull elk = m1 = 500kg m2 = 630 kg v1 = 45 m/s v2 = 45 m/s t = 0.5 s now set up conservation of momentum m1v1 + m2v2 = m1vf1 + m2vf2 (f is for final) plug in 50850 = 500vf1 + 630vf2 now use the formula for head on collisions vf1 = v1 * (m1-m2)/(m1+m2) vf2 = v1 * (2m1)/(m1+m2) i dont have much time to elaborate step by step on force remember that Impulse is Force * time OR the change in momentum mvf - mvo = F * t due to Newtons 3rd law, both get the same force use one elk's m, vo, vf and plug in should be easy stuff from there

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