1. A laser beam with wavelength ? = 6328 Å is incident normal to the plane of a
ID: 2011715 • Letter: 1
Question
1. A laser beam with wavelength ? = 6328 Å is incident normal to the plane of a
diffraction grating with a slit separation of d = 2000nm. If the diffraction
pattern is viewed on a screen 1m from the grating, find the distance separating
the first, second, and third maxima in the pattern.
2. A laser beam with wavelength ? = 6328 Å is incident normal to a single slit of
unknown width. If the slit is 417 mm from the screen, and the locations of the
first three minima are found to be:
m = 1: x = 4.4 mm,
m = 2: x = 8.8 mm,
m = 3: x = 13 mm,
find the width of the slit.
3. In a double slit apparatus, the slits are separated by 150µm. Light of
wavelength 5893Å is incident normal to the plane of the slits. An interference
pattern is observed on a screen 16.4 ft from the slits. Calculate the separation
between adjacent bright bands.
Explanation / Answer
Given wave length of laser beam = 6328 A o = 6328 Ao (10-10 m /1 Ao ) seperation between two slis d = 2000 nm distance between screen and slits L = 1 m condition for maxima Y = m L / d at m = 1 y = L / d = ( 6328*10-10 m ) ( 1 m ) / 2000*10-9 m = 0.3164 m at m = 2 y = 2 L / d = 2 ( 6328*10-10 m ) ( 1 m ) / 2000*10-9 m = 0.6328 m at m = 3 y = 3 L / d = 3 ( 6328*10-10 m ) ( 1 m ) / 2000*10-9 m = 0.9492 m As per rules please post one question per one post please post the remaining question as other post = 2 ( 6328*10-10 m ) ( 1 m ) / 2000*10-9 m = 0.6328 m at m = 3 y = 3 L / d = 3 ( 6328*10-10 m ) ( 1 m ) / 2000*10-9 m = 0.9492 m As per rules please post one question per one post = 3 ( 6328*10-10 m ) ( 1 m ) / 2000*10-9 m = 0.9492 m please post the remaining question as other postRelated Questions
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