\"Two pucks, of mass m and 4m, lie on a frictionless table. Equal forces are use

Question

"Two pucks, of mass m and 4m, lie on a frictionless table. Equal forces are used to push both bucks forward a distance of 1m. Which pick has the greater momentum upon completing the distance? Explain."

So in the first part, the problem asks to figure out which takes longer. I figured that the heaver 4m puck takes twice as long. Then, I thought that the answer to the question above would be that that same puck has the greater momentum.

Change in momentum = F * change in time.
Change in time for the heavier puck is twice as much and the forces are the same so: Change in momentum for 4m puck = F * 2 (change in time) as compared to
Change in momentum for m puck = F * (Change in time)
However, the explanation here on Cramster states that the momentum is the same because the force is the same. Can someone please further explain?

Explanation / Answer

Change in momentum = (force applied)(time of contact)                             p = Ft If forces are applied on the pucks during the same time, then the change in the momentum depends upon the applied force. In the problem, it is mentioned that, same force F is applied on both pucks, so change in momentum p is also same for both pucks.

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