<p>1. Consider a system of two converging thin lenses, L1 and L2, with focal len

Question

<p>1. Consider a system of two converging thin lenses, L1 and L2, with focal lengths 10cm<br />and 20cm respectively, separated by a distance of 80cm. A 5cm tall object located<br />15cm to the left of L1.</p>
<p>(a) Construct a ray diagram indicating the position and vertical orientation of<br />the intermediate image. Calculate this position and see that it matches your diagram.</p>
<p>(b) Find the position and magnification of the final image. Is the final image virtual or<br />real? Is it inverted or upright?</p>
<p>2. If you replace L2 with a diverging lens, will the final image be inverted or upright? If<br />you removed lens L1, leaving only the diverging lens, would you still be able to see<br />an image on the screen? Why or why not?</p>

Explanation / Answer

a) , b) 1/u =+1/v = 1/f For the first lens 1/v = 1/ 10- 1/ 15 v = 30 cm. For the second lens 1/v'= 1/f' - 1/u' u' = 80 -20 = 60 cm 1/v' = 1/20 -1/ 60 v' = 30 cm behind L2 real inverted image 2. 1/v'= 1/f' - 1/u' u' = 80 -20 = 60 cm f = -20cm 1/v' = - 1/20 -1/ 60 v' = - 15 cm infront of L2 virtual upright image is formed. ----------------------------- Diverging lens alone cannot produce real image and hence Cannot form image on a screed.

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