<p>The proton (charge 1.6x10^-19C, mass 1.7x10^-27Kg) and el

Question

<p>The proton (charge 1.6x10^-19C, mass 1.7x10^-27Kg) and electron (Charge -1.6x10^-19C,mass 9.1x10^-31kg) in a hydrogen atom are 5.3x10^-11m apart on average.</p>
<p>A)How much kinetic energy would the electrong need to escape to "a large distance" from the proton?(assuming the proton doesnt move)</p>
<p>B)How fast would the electron need to be moving in order to escape this way?</p>
<p>&#160;</p>
<p>Please explain each step clearly to recieve full kharma points</p>

Explanation / Answer

conservation of energy ;

K + P = 0 ;

m /2 [ v2 ^2 - v1^2 ] - kq^2 / r = 0

m /2 [ 0^2 - v1^2 ] - kq^2 / r = 0

KE needed = m / 2 [ v1^2 ] = kq^2 / r = ( 9 e 9 ) ( 1.6 e-19) ^2 / [ 5.3 e-11 ] = 4.347 e -18 J

b .

( 9.1 e-31 / 2 ) [ v1^2 ] = ( 9 e9 ) ( 1.6 e-19 )^2 / [ 5.3 e-11 ]

or v1 = 3.090 e 6 m /s

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