A coin rests 15.0 cm from the center of a turntable. The coefficient of static f

Question

A coin rests 15.0 cm from the center of a turntable. The coefficient of static friction between the coin and turntable surface is 0.350. The turntable starts from rest at t=0 and rotates with a constant angular acceleration of 0.730 rad/s^2. (a) Once the turntable starts to rotate, what force causes the centripetal acceleration when the coin is stationary relative to the turntable? Under what condition does the coin begin to move relative to the turntable? (b) After what period of time will the coin start to slip on the turntable?

Explanation / Answer

1. the coin will start moving when the force due to the centripetal acceleration of the table becomes more than the frictional force ....

2. time = 6.6333 sec

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