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The graph below shows the kinetic energy of a cart with respect to time. Use thi

ID: 2004816 • Letter: T

Question

The graph below shows the kinetic energy of a cart with respect to time. Use this graph to answer the following questions. State the time at which the velocity of the cart is zero. If the velocity was never zero then type 'never'. when is the cart traveling at a constant speed? How much work was done from 5 s to 50 s? When as the power zero? Calculate the power of the cart at t=3.9 s. Calculate the power of the cart at t=41.4s. The graph below shows the kinetic energy of a cart with respect to time. Use this graph to answer the following questions. State the tune at when the velocity of the cart is zero. If the velocity was never zero then type 'never'. when is the cart traveling at a constant speed? How much work was done from 5 s to 50 s? When as the power zero? Calculate the power of the cart at t=3.9 s. Calculate the power of the cart at t=41.4s.

Explanation / Answer

Graph - 1: (a) NEVER (b) 45 s to 50 s (c) Work = Change in KE                 = 300 J - 100 J                 = 200 J (d) 5 s to 50 s (e) Power = Slope of the graph at 3.9 s                  = (200 - 150) / (5-0)                  = 10 W (f) Power = Slope of the graph at 41.4 s                  = (300 - 0) / (45-30)                  = -16.67 W Magnitude of power = 16.67 W ---------------------------------------------------------------------- Graph - (2): (a) 20 s (b) 35 s to 50 s (c) Work = Change in KE                 = 200 J - 200 J                 = 0 J (d) 35 s to 50 s (e) Power = Slope of the graph at 13.2 s                  = (0 - 450) / (20-0)                  = - 22.5 W Magnitude of power = 22.5 W (f) Power = Slope of the graph at 31.6 s                  = (300 - 0) / (35-20)                  = 20 W                  = (300 - 0) / (45-30)                  = -16.67 W Magnitude of power = 16.67 W ---------------------------------------------------------------------- Graph - (2): (a) 20 s (b) 35 s to 50 s (c) Work = Change in KE                 = 200 J - 200 J                 = 0 J (d) 35 s to 50 s (e) Power = Slope of the graph at 13.2 s                  = (0 - 450) / (20-0)                  = - 22.5 W Magnitude of power = 22.5 W (f) Power = Slope of the graph at 31.6 s                  = (300 - 0) / (35-20)                  = 20 W (a) 20 s (b) 35 s to 50 s (c) Work = Change in KE                 = 200 J - 200 J                 = 0 J (d) 35 s to 50 s (e) Power = Slope of the graph at 13.2 s                  = (0 - 450) / (20-0)                  = - 22.5 W Magnitude of power = 22.5 W (f) Power = Slope of the graph at 31.6 s                  = (300 - 0) / (35-20)                  = 20 W                  = (300 - 0) / (35-20)                  = 20 W
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