Homework 2-1 Dimensio... X c Chegg Study I Guided sol... X 3 ebassign net t/web/

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Homework 2-1 Dimensio... X c Chegg Study I Guided sol... X 3 ebassign net t/web/Student/Assignment-Responses/submit?dep Search 313153 P Most visited Completed work Getting Started CS Employ Email BCS Google Docs BCS Google Calendar CS Google sites BCS Student Email Ombre Hair Extensions... American Horror Story A glider of length 10.4 cm moves on an air track with constant acceleration. A time interval of 0.623 s elapses between the moment when its front end passes a fixed point O along the track and the moment when its back end passes this point. Next, a time interval of 1.47 s elapses between the moment when the back end of the glider passes point and the moment when the front end of the glider passes a second point 3 farther down the track After that, an additional 0.458 elap s es until the back end of the glider passes point a) Find the average speed of the glider as it passes point cm/s (b) Find the acceleration of the glider cm/s (C) Explain how you can compute the acceleration without knowing the distance between points and

Explanation / Answer

Q1.Ans:Average speed at A is=(its own length)/(time interval to cross A)=10.4/0.623=16.53cm/sec.

Q2.Ans:The acceleration of the glider is=4.09 cm/sec2.

Q3.Ans:To calculate the acceleration we have to calculate the average speed at point B also.The glider crosses(its own length) the point A & B at time interval 0.623 &0.458 sec respectively.So from there we can calculate the average speed at A and B (Va & Vb say).Then the acceleration is=(Vb -Va)/(time interval to go from A to B).In this way we can calculate the acceleration without knowing the distance between A and B.

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