In a vacuum, two particles have charges of q1 and q2, where q1 = +2.8C. They are

Question

In a vacuum, two particles have charges of q1 and q2, where q1 = +2.8C. They are separated by a distance of 0.37 m, and particle 1 experiences an attractive force of 4.0 N. What is the value of q2, with its sign? In a vacuum, two particles have charges of q1 and q2, where q1 = +2.8C. They are separated by a distance of 0.37 m, and particle 1 experiences an attractive force of 4.0 N. What is the value of q2, with its sign? In a vacuum, two particles have charges of q1 and q2, where q1 = +2.8C. They are separated by a distance of 0.37 m, and particle 1 experiences an attractive force of 4.0 N. What is the value of q2, with its sign?

Explanation / Answer

F= kq1q2/r^2

Since the force is attractive, and first charge is positive, the other charge must be negative

q2 = Fr^2/kq1

q2 = - 4 *0.37^2/ 9*10^9 * 2.8

q2 = - 0.0217*10^-9 C

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