This question has parts A-I. Parts A, B, E, F, and G ask for expressions (formul

Question

This question has parts A-I. Parts A, B, E, F, and G ask for expressions (formulas). The other parts want numbers. Thank you!!!

(1496) Problem 7: In a simple AC circuit shown on the right, R = 45 ,dV= dVnsaxsin(m) where tax = 2.5 V, and = 55 rad/s. Randomized Variables R=45 AVmax = 8.5 V G) = 55 rad's AV ©theexpertta.com 1196 Part (a) Express the current lin terms oft, R, and Grade Summary 096 10096 7 8 9 cos(a) coo cos(9) | sin() sin psin(e) 0%ar os(p) | sin(cot) Submissions Attempts remaining: 296 per attempt) detailed view 6 END BACKSPACE Submit Hint Hints: 19% deduction per hint. Hints remaining:- Feedback: 1% deduction per feedback 1196 Part (b) Express the maximum of the current rman in terms ofAVta, and R. 11% Part (c) Calculate the numerical value of Ia in amps. 11% Part (d) How long (in seconds) does it take for the current Ito reach Ima (and be moving in the same direction) from the previous 1196 Part (e) Express the power dissipated in the circuit, P, in terms of land 1196 Part (f) Express the power dissipated in the circuit, P, as a function of time t and R, ,ax, and 11% Part (g) Express the maximum of P, Ptaz, in terms ofR and ¼az- à 1146 Part (h) Calculate the numerical value off," in watts. 11% Part () How long does it take for the power P to reach P from the previous Px in seconds.

Explanation / Answer

Here ,

a) as the impedance is given as

I = delta V/R

I = Vmax * sin(w * t)/R

b)

for the maximum current

Imax = Vmax/R

e)

Imax = Vmax/R

Imax = 8.5/45

Imax = 0.189 A

the current Imax is 0.189 A

d)

time period , T = 2pi/w

T = 2pi/55 s

T = 0.114 s

Now , time taken for one Imax to other Imax is 0.114 s

e)

Power dissipated = current * voltage

Power dissipated = V * I

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