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This question has se parts that must be completed sequentially. Ifyou skip a par

ID: 1795523 • Letter: T

Question

This question has se parts that must be completed sequentially. Ifyou skip a part of the question, you w able to come back to the skipped part not receive any ports for the skipped part, and you wil' not A 76.0-kg fullback running east with a speed of 5.10 m/'s is tackled by a 90.0-kg opponent running north with a speed of 3.00 m/s (a) Why does the tackle constitute a perfectly thelastie collision? (b) Caloulate the velocity of the players immediately after the tackle. (c) Determine the mechanical energy that is lost as a result of the collision. (e) Where did the lost energy go?

Explanation / Answer

v1 = 5.10 m/s i

m1 = 76 kg

m2 = 90 kg

v2 = 3 j


(A) after tackle both will move together. so colliison is perfectly inelastic collision.

(velocity of separation = 0 )


(b) Applying momentum conservtaion,


(76 x 5.10)i + (90 x 3)j = (76 + 90) v

v = 2.33i + 1.63 j

magnitude = sqrt(2.33^2 + 1.63^2) = 2.84 m/s

direction = tan^-1(1.63 / 2.33) = 35 deg


velocity = 2.84 m/s , 35 deg north of east  

(C) Ki = m1 v1^2 /2 + m2 v2^2 / 2 = 1393.4 J  

Kf = (m1 + m2) v^2 / 2 = 669.4 J  

Energy lost = Ki - Kf = 724 J

(d) in lost in form of sound or deformation .

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