35. Norman so enjoyed Developmental Biology that he deaided to do a genetic anal
ID: 199970 • Letter: 3
Question
35. Norman so enjoyed Developmental Biology that he deaided to do a genetic analysis of plant development for his thesis in graduate school Norman treated wild-lype plants with EMS, then let them sell-cross for multiple generations Norman obtained 5 plants that were short. Using these mutants, he set up and analyzed several crosses. Analyze these data sets and draw condusions phenotype of 1 X wt 2 X w 4Xwt wild type wild type wild type wild type 5 X wt short mutants intercrossed phenatype of P short X short F1 offspring 1 X2 1X3 1X4 1X5 short wild type wild type wild type 2 X3 2 x 4 2 X 5 wild type wild type wild type 3 X 4 3 x5 wild type short F1 plants X homozygous double mutants 90 short 10 wild type 25 wild type 75 shon 10 wild type 90 short 10 wild type 90 short 25 wild type 75 short 10 wild type 90 short 1 x 3 1X4 1x5 wild type X short wild type X short wild type X short 2X3 2 x4 2x5 wild type X short wild type X short wild type X short wid type X short 25 wild type 75 short 13 Chagte 4 Homework ProbiensExplanation / Answer
Conclusions:
i. All the mutations in heterozygous condition do not show the phenotype. So, they all must be recessive mutations.
ii. If the F1 of a cross between two recessive mutants shows mutant phenotype, it means that both the mutants are allelic to each other.
So, mutant 1 = mutant 2 and mutant 3 = mutant 5
iii.
1 X 3
AaCc X aacc
AaCc Aacc aaCc aacc
Expected progeny = 3 (short): 1 WT
Observed = 1 (WT) : 9 short
So, it does not follow typical mendelian inheritance pattern.
It is difficult to explain this inheritance pattern.
1 X 4
AaDd X aadd
AaDd Aadd aaDd aadd
Expected progeny = 3 (short): 1 WT
Observed = 3 (short): 1 WT
So, it follows typical Mendelian inheritance pattern.
Similarly, all the other cross can be inferred.
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.