NAME: PHYSICS 235 TEST 2 DATE: FALL, 2016 Average Speed total distance total tim
ID: 1998378 • Letter: N
Question
NAME: PHYSICS 235 TEST 2 DATE: FALL, 2016 Average Speed total distance total time Average velocity total displacement/total time AVAt G-6.67 v 10 N m kg' Vi at g 9.8 m/s M, 5.98 x 10" kg AX Vi t a t RE 6,4 x 10 m NA 6.02 x 10 /mole 2 a 400 2, a AX R 8.31 J/mole-K F.et m aart k 1.38 x 101 J/K W (work) F d Cos 0 P (power) W /t W.et KE KE. work-energy theorem I atm .01 x 10' Pa 1 gm/cm'- 10' kg/ m' P.E K.Er P.Er frd K.Ei AK.E P (momentum MV J (impulse)- F At AP Xom (mi xi m: x: y m, m. Conservation of momentum: M, vut M. V M Virt. M. V Via V Elastic collision: at ra UG -GM m/rExplanation / Answer
m1= 5 Kg
m2 = 3 Kg
u = 0.30
let the acceleration of the system is a
using second law of motion
a = net force/total effective mass
a = (3 * 9.8 - 0.30 * 5 * 9.8)/(3 + 5)
a = 1.84 m/s^2
the acceleration of the blocks is 1.84 m/s^2
for the tension T
3 * 9.8 - T = 3 * 1.84
T = 23.9 N
the tension in the string is 23.9 N
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