problem in the table refers to a different combination of lenses and different v
ID: 1997822 • Letter: P
Question
problem in the table refers to a different combination of lenses and different values for distances, which are given in centimeters. The type of lens is indicated by C for converging and D for diverging; the number after Cor Dis the distance between a lens and either of its focal points (the proper sign of the focal distance is not indicated). Find (a) the image distance iz for the image produced by lens 2 (the final image produced by the system) and (b) the overall lateral magnification M for the system including signs. Also, determine whether the final image is (c) real or virtual, (d) inverted from object o or noninverted, and (e) on the same side of lens 2 as object o or on the opposite side (a) (b) (c) (d) (e) Lens 1 d Lens 2 R/V I/NI Side p1 C, 19 12 C, 9.3 +20 Units Tcm (a) Numbe 19.526 (b) Numbe 0.46 Unit This answer has no units (c) reaExplanation / Answer
for lens1:
f1 = +19 cm
p1 = +20 cm
Appying lens equation,
1/f1 = 1/p1 + 1/q1
q1 = p1 f1 / (p1 - f1) = 380 cm
now for lens 2:
f2 = + 9.3 cm
image by lens 1 will work as object for lens 2.
p2 = 12 - 380 = - 368 cm
1/9.3 = 1/(-368) + 1/q2
q2 = - 9.071 cm
(A)distance of final image from lens 2 = 9.071 cm
(B) M = (-q1/p1)(q2/p2)
= (380/20) (-9.071/-368)
= 0.468
(c) Real
(D) M is positive hence non-inverted.
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