8. A parallel plate capacitor starts off filled with air of dielectric constant

Question

8. A parallel plate capacitor starts off filled with air of dielectric constant Kair and con- nected to a battery of voltage, Vb. Then a glass dielectric with dielectric constant Kglass is inserted into the the capacitor (Kglass > Kair). Assume the glass dielectric completely fills the capacitor. Which best describes what happens to the amount of charge on each of the plates (Q) and the voltage across the plates (V )? A. Q increases, and V decreases. B. Q decreases, and V stays the same. C. Q decreases, and V increases. D. Q increases, and V stays the same. 8. A parallel plate capacitor starts off filled with air of dielectric constant Kair and con- nected to a battery of voltage, Vb. Then a glass dielectric with dielectric constant Kglass is inserted into the the capacitor (Kglass > Kair). Assume the glass dielectric completely fills the capacitor. Which best describes what happens to the amount of charge on each of the plates (Q) and the voltage across the plates (V )? A. Q increases, and V decreases. B. Q decreases, and V stays the same. C. Q decreases, and V increases. D. Q increases, and V stays the same. 8. A parallel plate capacitor starts off filled with air of dielectric constant Kair and con- nected to a battery of voltage, Vb. Then a glass dielectric with dielectric constant Kglass is inserted into the the capacitor (Kglass > Kair). Assume the glass dielectric completely fills the capacitor. Which best describes what happens to the amount of charge on each of the plates (Q) and the voltage across the plates (V )? A. Q increases, and V decreases. B. Q decreases, and V stays the same. C. Q decreases, and V increases. D. Q increases, and V stays the same.

Explanation / Answer

Here ,

when the dielectric is inserted in the capacitor ,

as the dielectric constant of glass is more than the dielectric constant of air

the capacitance of capacitor will increase

as the capacitor is connected to battery , the potential will remain constant and the charge on the capacitor will increase

the correct option is

D. Q increases, and V stays the same.

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