Hello, this is from thermodynamics problem. I will rate the answer according to

Question

Hello, this is from thermodynamics problem.

I will rate the answer according to its completeness and legiblity.

My initial thought is to first calculate the amount of work (J) needed by 65kg person to climb 10m (W = F * d)

and calculate how much moles of glucose oxidation is needed using the given gibbs free energy.

Only I don't know how to do that exactly,

Many thanks in advance.

The change in Gibbs energy that accompanies the oxidation of C&H120s; (s) to carbon dioxide and water vapor at 25°C is -2808 kJ mol1. How much glucose does a person of mass 65 kg need to consume to climb through 10 m? Hint: think about how much work is done (in Joules) while climbing 4.

Explanation / Answer

energy required to climb 10 m = mgh

= 65*9.8*10 = 6370 J

moles of glucose required to climb

= 6370 / (2808*1000)

= 0.0030625 moles

Related Questions

Navigate

• Browse (All)
• Browse H
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.