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A cart of mass 10 kg shown above moves without frictional loss on a level table.

ID: 1996954 • Letter: A

Question

A cart of mass 10 kg shown above moves without frictional loss on a level table. A 10 N force pulls on the car horizontally to the right. At the same time, a 30 N force at an angle of 60 degree above the horizontal pulls on the cart to the left. What is the magnitude of the horizontal acceleration of the cart? 0.5 m/s^2 1.6 m/s^2 2.0 m/s^2 2.5 m/s^2 2.6 m/s^2 An object has a weight W when it is on the surface of a planet of radius R What will be the gravitational force on the object after it has been moved to a distance of 4 R from the center of the planet 16 W 4 W W 1/16 W

Explanation / Answer

here,

5)

mass , m = 10 kg

F1 = 10 N

F2 = 30 N , theta = 60 degree

the magnitude of the horizontal accelration , a = ( F2 * cos(theta) - F1) /m

a = ( 30 * cos(60) - 10) /10

a = 0.5 m/s^2

the horizontal accelration is A) 0.5 m/s^2

6)

when R' = 4 * R

the accelration due to gravity , g' = G * M /R'^2

g' = G * M /( 4 * R)^2

g' = g/16

weight of the object , W = m * g

as g' = g/16

W' = W/16

the gravitational force on the object is E) W/16

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