Two bumper cars in an amusement park directly from the rear (see figure below),

Question

Two bumper cars in an amusement park directly from the rear (see figure below), Car A has a mass of 650 kg and car differences in passenger mass. If car A approaches at 5.70 m/s and car ft is moving the speed of the car A after the collision using 75F for your final answer, the speed of the car B after the collision using 75F for your final answer, the change in momentum of the A, lambda p lambda using 75F for your final answer, the change in momentum of the A, lambda ps using 75F for your final answer, Compare answers (c) and (d), Explain. What can you tell about the change in the total momentum?

Explanation / Answer

m1v1+m2v2=m1vi+m2vk; if v1 and v2 are initial velocities and vi,vk are final velocities the conserving energy we have; 0.5m1v1^2+0.5m2v2^2=0.5m1vi^2+0,5m2vk^2; we get vi=(m1-m2)/(m1+m2)v1+(2m2)/(m1+m2)v2; vk=(2m1)/(m1+m2)v1+(m1-m2)/(m1+m2)v2; therefore vi=396m/s; vk=626.3m/s

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