Two boxes, one of mass m2 and one of mass m1 are connected via a rope and pulley

Question

Two boxes, one of mass m2 and one of mass m1 are connected via a rope and pulley. Assume the rope has no mass, pulley has no mass and no friction, and there is no friction between m1 and the table. The positive x-axis is to the right and the positive y-axis is up.

How does the net force on box m1 compare to the weight of m2?

a: net force on box m1<weight of box m2

b: net force on box m1= weight box m2

c: not enough info

d: Net force box m1> weight box m2

e: none of the above

How does the net force on box m2 compare to the weight of box m2?

a: net force box m2> weight box m2

b: net force box m2<weight box m2

c: net force in box m2= weight box m2

d: not enough info

e: none of the above

Explanation / Answer

Part A)

Since the surface is frictionless, the system will accelerate such that m2 drops and m1 moves to the right under the force of Tension in the rope.

Since m2 drops its weight is greater then the Tenison in the rope.

The tension is the net force on m1 and that is less then m2, so...

Therefore the answer is choice a: net force on box m1<weight of box m2

Part B)

By the same factors, the net force on m2 is less than its weight since there is a Tension pulling up.

Thus choice b is the answer here... net force box m2<weight box m2

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