Question Details When an x-ray beam is scattered off the planes of a crystal, th

Question

Question Details When an x-ray beam is scattered off the planes of a crystal, the scattered beam creates an interference pattern. This phenomenon is called Bragg scattering. For an observer to measure an interference maximum, two conditions have to be satisfied: The angle of incidence has to be equal to the angle of reflection. The difference in the beam's path from a source to an observer for neighboring planes has to be equal to an integer multiple of the wavelength; that is, . The path difference can be determined from the diagram . The second condition is known as the Bragg condition. A: An x-ray beam with wavelength 0.150 nm is directed at a crystal. As the angle of incidence increases, you observe the first strong interference maximum at an angle 21.5^degree. What is the spacing d between the planes of the crystal? d= ? nm B: Find the angle theta_2 at which you will find a second maximum. theta_2= ? (degree)

Explanation / Answer

x-ray beam wavelength w= 0.150 nm = 0.15 * 10 ^ -9 m angle of first strong interference maximum theta = 21.5 degrees the spacing between the planes of the crystal d = ? we know 2d sin ( theta ) = w from this d = w / [ 2 sin (theta ) ] = (B). The angle of a second maximum theta ' = ? we know 2d sin (theta') = 2 w from this sin ( theta ') = w / d Theta ' =

Related Questions

Navigate

• Browse (All)
• Browse Q
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.